16x^2-368x+2035=0

Solution for 16x^2-368x+2035=0 equation:

16x^2-368x+2035=0

a = 16; b = -368; c = +2035;
Δ = b2-4ac
Δ = -3682-4·16·2035
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-368)-72}{2*16}=\frac{296}{32}
=9+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-368)+72}{2*16}=\frac{440}{32}
=13+3/4
$